Let \(s\) be a real number. Let \(n\) be a natural number. Then \(r\) is an \(n^{th}\)-root of \(s\) provided
The symbol for the \(n^{th}\)-root of \(s\) uses the radical sign, \(\sqrt [n]{s}\).
Even Roots
This course is the study of the real numbers. As a result we don’t take even roots of negative numbers.
Even roots
look a lot like the square root
Their domains do not include negative numbers: \([0, \infty )\). Their domains are the nonnegative numbers. These functions increase very slowly over their domain, becoming unbounded.
The graph of \(y = SR(x) = \sqrt {x}\)
The square root function begins where the inside of the radical equals \(0\). It then moves in the direction that keeps the inside positive.
The graph of \(y = f(v) = \sqrt {v+3}\)
Here the inside \(v+3\) equals \(0\) when \(v=\answer {-3}\). That is the start of the domain. Then, the inside is positive \(v+3>0\), when \(v>-3\), which means the graph moves up to the right.
The graph of \(y = T(k) = \sqrt {-k+5}\)
Here the inside \(-k+5=0\) equals \(0\) when \(k=\answer {5}\). That is the start of the domain. Then the inside is positive \(-k+5>0\), when \(k\) \(<\) \(>\) \(5\), which means the graph moves up to the left. The domain is \((-\infty ,5]\).
Odd Roots
This course is the study of the real numbers. As a result we don’t take even roots of negative numbers, however we do have odd roots of negative numbers
Odd roots
look a lot like the cube root
Their domains include all real numbers: \((-\infty , \infty )\). Odd root functions increase very slowly over this domain, becoming unbounded.
The graph of \(y = CubeRoot(x) = \sqrt [3]{x}\)
The cube root function has a vertical tangent line where the inside of the radical equals \(0\).
The graph of \(y = f(v) = \sqrt [3]{v+3}\)
Here the inside \(v+3\) equals \(0\) when \(v=\answer {-3}\). The graph has a vertical tangent line there. Otherwise, the cube root function is increasing everywhere, but increasing slower and slower and slower.
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