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Various exercises relating to partial fractions and integration.

Compute the indefinite integrals below. Since there are many possible answers (which differ by constant values), use the given instructions if needed to choose which possible answer to use. Do not forget absolute value signs inside logarithms when they are needed.
(Do not include any constant terms in your antiderivative.)
(Do not include any constant terms in your antiderivative.)
(Do not include any constant terms in your antiderivative.)
Don’t forget polynomial long division; it is needed in this case because the degree of the numerator is at least as large as the degree of the denominator.
Since the derivative of the denominator is $2x + 4$, we should rewrite the numerator of the big fraction to have $x+2$’s if possible: For expressions like we should do a substitution. For terms like we should first complete the square: $x^2 + 4x + 10 = (x + 2)^2 + 6$ and then make the substitution $x + 2 = u \sqrt {6}$.

### Sample Quiz Questions

Compute the integral (Hints won’t be revealed until after you choose a response.)

$\displaystyle \ln 2$ $\displaystyle \ln 3$ $\displaystyle \ln 4$ $\displaystyle \ln 5$ $\displaystyle \ln 6$ $\displaystyle \ln 7$

### Sample Exam Questions

Compute the volume of the solid of revolution obtained by revolving around the $y$-axis the region below the graph above $y=0$, and between $x=2$ and $x=3$. (Hints won’t be revealed until after you choose a response.)
$\displaystyle \pi$ $\displaystyle \pi ( \ln 2 + 3)$ $\displaystyle \pi (2 \ln 2 + 1)$ $\displaystyle \pi (2 \ln 3 + 1)$ $\displaystyle \pi (3 \ln 2 + 1)$ $\displaystyle \pi (3 \ln 3 + 1)$

Compute the constants $A$ and $B$ in the partial fractions expansion indicated below. To receive full credit, it is not necessary to compute $C, D,$ or $E$. (Hints won’t be revealed until after you choose a response.)

$A=-1, B=1$ $A = 0, B = 1$ $A = 1, B = 1$ $A=-1, B=-1$ $A = 0, B = -1$ $A = 1, B = -1$

Evaluate $\displaystyle \int _1^2 \frac {x^2+x+1}{x^2+x} dx$.

$0$ $1$ $\displaystyle 1 + \ln \left (\frac {4}{3}\right )$ $2$ $\displaystyle 2 + \ln \left (\frac {8}{3}\right )$ none of these