- (a)
- Beginning with the given figure on the left, Morgan draws and marks the figure intending that this new segment is a(n) medianangle bisectorperpendicular bisectoraltitude .
- (b)
- Based on the marked figure, Morgan claims that the by SASSSSSSAASAHL .
- (c)
- Finally, Morgan concludes that , as they are corresponding parts of congruent triangles.
Four proofs and one almost.
Any (or all) of the proofs might be extended to conclude that, in the case of an isosceles triangle, the perpendicular bisector, angle bisector, median, and altitude all lie on the same line.
- (a)
- Beginning with the given figure on the left, Deja draws and marks the figure intending that this new segment is a(n) medianangle bisectorperpendicular bisectoraltitude .
- (b)
- Based on the marked figure, Deja claims that the by SASSSSSSAASAHL .
- (c)
- Finally, Deja concludes that , as they are corresponding parts of congruent triangles.
- (a)
- Beginning with the given figure on the left, Elle draws and marks the figure intending that this new segment is a(n) medianangle bisectorperpendicular bisectoraltitude .
- (b)
- Based on the marked figure, Elle claims that the by SASSSSSSAASAHL .
- (c)
- Finally, Elle concludes that , as they are corresponding parts of congruent triangles.
Beginning with the given figure on the left, Simon draws and marks the second figure intending that this new segment is a perpendicular bisector of .
Taylor claims that a perpendicular bisector of a side of a triangle usually misses the opposite vertex, so the figure should allow for that possibility.
Fix note: Taylor’s claim, the prompt, and the choices below need attention. Simon’s figure suggests congruence by “SSAS,” which might indicate that too much is being assumed. Would that make sense as a distractor?
Without using other facts about isosceles triangles or perpendicular bisectors, choose the best assessment of their disagreement:
- (a)
- Examining the given figure on the left, Lissy notices symmetry in the triangle and claims that the triangle is congruent to itself by a translationreflectionrotation .
- (b)
- Based on the marked figure, Lissy claims that the by SASSSSSSAASAHL .
- (c)
- Finally, Lissy concludes that , as they are corresponding parts of congruent triangles.