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Mathematical Expression Editor
Solved Problems for Chapter 7
Let . When doing cofactor expansion along the top row, we encounter three minor
matrices. What are they?
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Find the following determinant by (a) expanding along the first row, (b) second
column.
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Compute the determinant by co-factor expansion. Pick the easiest row or column to
use.
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Expand along the third row.
An operation is done to get from the first matrix to the second. Identify
what was done and tell how it will affect the value of the determinant. \begin{equation*} \left [ \begin{array}{cc} a & b \\ c & d \end{array} \right ] \rightarrow \cdots \rightarrow \left [ \begin{array}{cc} a & c \\ b & d \end{array} \right ] \end{equation*}
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It does not change the determinant. This was just taking the transpose.
An operation is done to get from the first matrix to the second. Identify
what was done and tell how it will affect the value of the determinant. \begin{equation*} \left [ \begin{array}{cc} a & b \\ c & d \end{array} \right ] \rightarrow \cdots \rightarrow \left [ \begin{array}{cc} c & d \\ a & b \end{array} \right ] \end{equation*}
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In this case two rows were switched and so the resulting determinant is times the
first.
An operation is done to get from the first matrix to the second. Identify
what was done and tell how it will affect the value of the determinant. \begin{equation*} \left [ \begin{array}{cc} a & b \\ c & d \end{array} \right ] \rightarrow \cdots \rightarrow \left [ \begin{array}{cc} a & b \\ a+c & b+d \end{array} \right ] \end{equation*}
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The determinant is unchanged. It was just the first row added to the second.
An operation is done to get from the first matrix to the second. Identify
what was done and tell how it will affect the value of the determinant. \begin{equation*} \left [ \begin{array}{cc} a & b \\ c & d \end{array} \right ] \rightarrow \cdots \rightarrow \left [ \begin{array}{cc} a & b \\ 2c & 2d \end{array} \right ] \end{equation*}
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The second row was multiplied by 2 so the determinant of the result is 2 times the
original determinant.
An operation is done to get from the first matrix to the second. Identify
what was done and tell how it will affect the value of the determinant. \begin{equation*} \left [ \begin{array}{cc} a & b \\ c & d \end{array} \right ] \rightarrow \cdots \rightarrow \left [ \begin{array}{cc} b & a \\ d & c \end{array} \right ] \end{equation*}
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In this case the two columns were switched so the determinant of the second is times
the determinant of the first.
Let be an matrix and suppose there are rows such that all rows are linear
combinations of these rows. Show .
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If the determinant is nonzero, then it will remain nonzero with row operations
applied to the matrix. In this case, you can obtain a row of zeros by doing row
operations. Thus the determinant must be zero.
Construct matrices and to illustrate the property that .
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An matrix is called nilpotent if for some positive integer, it follows If is a
nilpotent matrix and is the smallest possible integer such that what are the possible
values of ?
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because
A matrix is said to be orthogonal if Thus the inverse of an orthogonal matrix
is just its transpose. What are the possible values of if is an orthogonal
matrix?
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You would need and so or .
Let and be two matrices. We say that is similar to and write provided that
there exists an invertible matrix such that Show that if then .
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.
Determine whether each statement is true or false. If true, provide a proof. If false,
provide a counter example.
(a)
If any two columns of a square matrix are equal, then the determinant of
the matrix equals zero.
(b)
If exists then
(c)
If is a real matrix, then
(d)
If for some then
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All of the statements are true.
(a)
. If two columns of are equal, then two rows of are equal. Applying row
operations to will produce a matrix with a row of zeros.
(b)
Suppose is invertible. Then
Divide both right and left side by to obtain the result.
(c)
This follows from the fact that .
(d)
If for some then there is a non-trivial linear combination of the columns of
that is equal to . This means that the columns of are linearly dependent.
This implies that the rows are also linearly dependent (why?). Applying
elementary row operations will lead us to a row of zeros.
Let \begin{equation*} A = \left [ \begin{array}{rrr} 1 & 0 & 3 \\ 1 & 0 & 1 \\ 3 & 1 & 0 \end{array} \right ] \end{equation*}
Determine whether the matrix has an inverse by finding whether the determinant is
non-zero.
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and so it has an inverse. The inverse turns out to equal