Dot Product and its Properties

Note that the dot product of two vectors is a scalar. For this reason, the dot product is sometimes called a scalar product.

Properties of the Dot Product

A quick examination of Example ex:dotex will convince you that the dot product is commutative. In other words, . This and other properties of the dot product are stated below.

We will prove Property  item:distributive. The remaining properties are left as exercises.

Proof of Property item:distributive:

\begin{align*} \left (\vec{u}+\vec{v}\right )\dotp \vec{w}&=\left (\begin{bmatrix} u_1\\ u_2\\ \vdots \\ u_n \end{bmatrix}+\begin{bmatrix} v_1\\ v_2\\ \vdots \\ v_n \end{bmatrix}\right )\dotp \begin{bmatrix}w_1\\w_2\\\vdots \\w_n\end{bmatrix}=\begin{bmatrix} u_1+v_1\\ u_2+v_2\\ \vdots \\ u_n+v_n \end{bmatrix}\dotp \begin{bmatrix}w_1\\w_2\\\vdots \\w_n\end{bmatrix}\\ &=(u_1+v_1)w_1+ (u_2+v_2)w_2+ \ldots + (u_n+v_n)w_n\\ &=u_1w_1+v_1w_1+ u_2w_2+v_2w_2+ \ldots + u_nw_n+v_nw_n\\ &=(u_1w_1+ u_2w_2\ldots +u_nw_n)+(v_1w_1+v_2w_2+ \ldots +v_nw_n)\\ &=\begin{bmatrix} u_1\\ u_2\\ \vdots \\ u_n \end{bmatrix}\dotp \begin{bmatrix}w_1\\w_2\\\vdots \\w_n\end{bmatrix}+\begin{bmatrix} v_1\\ v_2\\ \vdots \\ v_n \end{bmatrix}\dotp \begin{bmatrix}w_1\\w_2\\\vdots \\w_n\end{bmatrix} =\vec{u}\dotp \vec{w}+\vec{v}\dotp \vec{w} \end{align*}

We will illustrate Property item:norm with an example.

If we take the square root of both sides of the equation in Property item:norm, we get an alternative way to think of the length of a vector.

Practice Problems

Find the dot product of and if Answer:
Find the dot product of and if Answer:

Use vector to illustrate Property item:norm of Theorem th:dotproductproperties.
From the given list of vector pairs, identify ALL pairs of vectors that lie on perpendicular lines.
You may want to draw a picture and think about what you know about slopes of perpendicular lines.
, , , ,
Compute for each pair. What do you observe?

Problems prob:perpvectors2a-prob:perpvectors2c

For each problem below

(a)
Find the value of that will make vectors and perpendicular. (Hint: Think of the -component as the “run” and the -component as the “rise”, then use what you know about slopes of perpendicular lines.)
(b)
Find .

Answer:

Answer:
Answer:
(a)
Vector that lies on the line , has the form . Assuming that , find the general form for a vector that lies on a line perpendicular to .
What do you know about the slopes of perpendicular lines?
(b)
Find .
(c)
Formulate a conjecture about the dot product of perpendicular vectors.
2024-09-26 23:11:02