Two young mathematicians think about trigonometric functions.

Check out this dialogue between two calculus students (based on a true story):
Devyn
Riley, do you remember talking about trig equations a while ago?
Riley
Absolutely! We used trig identities to simplify the equation, then built triangles to find reference angles.
Devyn
Right., but if I have a trig equation like ....
Riley
SOH-CAH-TOA, so sine is opposite over hypotenuse. We build a triangle whose opposite side has length , and whose hypotenuse is . The other side is given by .
Devyn
Yes, but what is the angle! That’s not one of the triangles whose angles I remember.
Riley
Oh no! What do we do?
Recall that two functions and are inverses of one another if both:
  • for all in the domain of .
  • for all in the domain of .

What condition do we need in order for a function to have an inverse?

Does the function have an inverse?
Is the inverse of ?
Find the solution of that lies in the interval .