A right circular cone is to be made with a fixed slant height of 8 ft.
The height that maximizes the volume of the cone is
\[ h = \answer {\frac {8}{\sqrt {3}}} \]
Hint: The volume of the cone is \(\frac {\pi r^2h}{3}\), where \(h\) is the height of the cone and \(r\) is the radius.