\[ \lim _{x\to 3}\frac {x^{2}-4x+1}{3-x} \]
The limit is of determinate form. The limit is of indeterminate form. The limit
is of the form \(\dfrac {0}{0}\). The limit is of the form \(\dfrac {\#}{0}\).
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Evaluate the limit. Possible answers include a number, \(+\infty \), \(-\infty \) and \(DNE\).
\[ \lim _{x\to 3^{+}}\frac {x^{2}-4x+1}{3-x}=\answer {+\infty } \]
Justify your answer
by choosing all correct statements. The numerator is negative and the
denominator is positive and approaching zero. The numerator is positive
and the denominator is positive and approaching zero. The numerator
is positive and the denominator is negative and approaching zero. The
numerator is negative and the denominator is negative and approaching zero.
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Evaluate the limit. Possible answers include a number, \(+\infty \), \(-\infty \) and \(DNE\).
\[ \lim _{x\to 3^{-}}\frac {x^{2}-4x+1}{3-x}=\answer {-\infty } \]
Justify your answer
by choosing all correct statements. The numerator is negative and the
denominator is positive and approaching zero. The numerator is positive
and the denominator is positive and approaching zero. The numerator
is positive and the denominator is negative and approaching zero. The
numerator is negative and the denominator is negative and approaching zero.
_
Evaluate the limit. Possible answers include a number, \(+\infty \), \(-\infty \) and \(DNE\).
\[ \lim _{x\to 3}\frac {x^{2}-4x+1}{3-x}=\answer {DNE} \]
Justify your answer
by choosing the correct statement.
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