Consider the function

\[ f(x) = \begin{cases} \frac {x^2-x-12}{x+3} & \text {if }x<4\text { and }x\neq -3\\ \\ c & \text {if }x=-3\\ \\ \frac {e^x}{x-4} & \text {if }x>4 \end{cases} \]

Find the value of \(c\) that makes \(f\) continuous on its domain.

\[c=\answer {-7}\]