Consider a particle moving along a straight line. The figure below gives the velocity function of the particle. Assume that at \(t=0\) the particle is at the origin. The velocity is measured in m/s and time in seconds.

The displacement of the particle between \(t=0\) and \(t=8\) is \(\answer {-1}\) m.

The average velocity of the particle on the interval \([0,8]\) is \(\answer {-\frac {1}{8}}\) m/s.

The total distance traveled between \(t=0\) and \(t=8\) is \(\answer {5}\) m.

The position of the particle at \(t=3\) is \(\answer {\frac {7}{4}}\) m.

The position of the particle at \(t=5\) is \(\answer {\frac {7}{4}}\) m.

The position function, \(s(t)\) for \(6\le t\le 8\) is given by

\[ s(t) = \answer {7-t} m. \]

The acceleration function for the particle on the interval \([6,8]\) is

\[ a(t) = \answer {0} m/s^2. \]