f1ee11…: “Such as a fine book”

$\newenvironment {prompt}{}{} \newcommand {\accordion }[0]{} \newcommand {\ungraded }[0]{} \newcommand {\xmDefaultPreamble }[0]{xmPreamble.tex} \newcommand {\xmDefaultPrintstyle }[0]{xmPrintstyle.sty} \newcommand {\todo }[0]{} \newcommand {\oiint }[0]{{\large \bigcirc }\kern -1.56em\iint } \newcommand {\mooculus }[0]{\textsf {\textbf {MOOC}\textnormal {\textsf {ULUS}}}} \newcommand {\sagemath }[0]{\textsf {SageMath}} \newcommand {\surfaceColor }[0]{violet} \newcommand {\surfaceColorTwo }[0]{redyellow} \newcommand {\sliceColor }[0]{greenyellow} \newcommand {\vector }[1]{\left \langle #1\right \rangle } \newcommand {\sectionOutcomes }[0]{}$

$\log _2(1)$ $<$ $>$ $\log _2(2)$.

$\log _2(2)$ $<$ $>$ $\log _2(3)$.

$\log _2(3)$ $<$ $>$ $\log _2(4)$.

$\log _2(4)$ $<$ $>$ $\log _2(5)$.

$\log _2(5)$ $<$ $>$ $\log _2(6)$.

If $0 < a < b$, then $\log _2(a)$ $<$ $>$ $\log _2(b)$.

$L(x) = \log _2(x)$ is a(n) increasing decreasing .

$\log _{\tfrac {1}{3}}(1)$ $<$ $>$ $\log _{\tfrac {1}{3}}(2)$.

$\log _{\tfrac {1}{3}}(2)$ $<$ $>$ $\log _{\tfrac {1}{3}}(3)$.

$\log _{\tfrac {1}{3}}(3)$ $<$ $>$ $\log _{\tfrac {1}{3}}(4)$.

$\log _{\tfrac {1}{3}}(4)$ $<$ $>$ $\log _{\tfrac {1}{3}}(5)$.

$\log _{\tfrac {1}{3}}(5)$ $<$ $>$ $\log _{\tfrac {1}{3}}(6)$.

If $0 < a < b$, then $\log _{\tfrac {1}{3}}(a)$ $<$ $>$ $\log _{\tfrac {1}{3}}(b)$.

$M(x) = \log _{\tfrac {1}{3}}(x)$ is a(n) increasing decreasing .

2025-05-17 17:44:55