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Mathematical Expression Editor
Challenge Problems for Chapter 8
Suppose \(A\) is an \(n\times n\) matrix consisting entirely of real entries but \(a+ib\) is a complex
eigenvalue having the eigenvector, \(\vec {x}+i\vec {y}\) Here \(\vec {x}\) and \(\vec {y}\) are real vectors. Show that then \(a-ib\) is
also an eigenvalue with the eigenvector, \(\vec {x}-i\vec {y}\).
You should remember that the conjugate of a product of complex numbers equals
the product of the conjugates. Here \(a+ib\) is a complex number whose conjugate equals
\(a-ib.\)
Click the arrow to see the answer.
\(AX=\left ( a+ib\right )X\). Now take conjugates of both sides. Since \(A\) is real,
If \(A\) is \(2 \times 2\) and diagonalizable, show that \(C(A) = \{X \mid XA = AX\}\) has dimension \(2\) or \(4\).
If \(P^{-1}AP = D\), show that \(X\) is in \(C(A)\) if
and only if \(P^{-1}XP\) is in \(C(D)\).
Let \(A\) be \(n \times n\) with \(n\) distinct real eigenvalues. If \(AC = CA\), show that \(C\) is diagonalizable.
Given a polynomial \(p(z) = r_{0} + r_{1}z + \dots + r_{n}z^{n}\) and a square matrix \(A\), the matrix \(p(A) = r_{0}I + r_{1}A + \dots + r_{n}A^{n}\) is called the evaluation of \(p(z)\)
at \(A\). Let \(B = P^{-1}AP\). Show that \(p(B) = P^{-1}p(A)P\) for all polynomials \(p(x)\).
If \(A\) is diagonalizable and \(p(x)\) is a polynomial such that \(p(\lambda ) = 0\) for all eigenvalues \(\lambda \) of \(A\), show
that \(p(A) = O\) (here, the final O is the zero matrix the same size as \(A\)).
The characteristic polynomial of \(A\) (see Definition ??) certainly satisfies the
requirement that \(p(\lambda ) = 0\) for all eigenvalues \(\lambda \) of \(A\). In solving this problem you have proved a
special case of the Cayley-Hamilton theorem, see Theorem ??. In fact, if \(p(\lambda )\) is
the characteristic polynomial of \(A\), then \(p(A) = 0\) whether or not \(A\) is diagonalizable.
Let \(P\) be an invertible \(n \times n\) matrix. If \(A\) is any \(n \times n\) matrix, write \(T_{P}(A) = P^{-1}AP\). Verify that:
(a)
\(T_{P}(I) = I\)
(b)
\(T_{P}(AB) = T_{P}(A)T_{P}(B)\)
(c)
\(T_{P}(A + B) = T_{P}(A) + T_{P}(B)\)
(d)
\(T_{P}(rA) = rT_{P}(A)\)
(e)
\(T_{P}(A^{k}) = [T_{P}(A)]^{k}\) for \(k \geq 1\)
(f)
If \(A\) is invertible, \(T_{P}(A^{-1}) = [T_{P}(A)]^{-1}\).
(g)
If \(Q\) is invertible, \(T_{Q}[T_{P}(A)] = T_{PQ}(A)\).
Let \(A = \begin{bmatrix} 0 & a & b \\ a & 0 & c \\ b & c & 0 \end{bmatrix}\) and \(B = \begin{bmatrix} c & a & b \\ a & b & c \\ b & c & a \end{bmatrix}\).
(a)
Show that \(x^{3} - (a^{2} + b^{2} + c^{2})x - 2abc\) has real roots by considering \(A\).
(b)
Show that \(a^{2} + b^{2} + c^{2} \geq ab + ac + bc\) by considering \(B\).
Assume the \(2 \times 2\) matrix \(A\) is similar to an upper triangular matrix. If \(\mbox {tr} A = 0 = \mbox {tr} A^{2}\), show that \(A^{2}\) is
equal to the zero matrix.
Show that \(A\) is similar to \(A^{T}\) for all \(2 \times 2\) matrices \(A\).
Let \(A =\begin{bmatrix} a & b \\ c & d \end{bmatrix}\). If \(c = 0\) treat the cases \(b = 0\) and \(b \neq 0\)
separately. If \(c \neq 0\), reduce to the case \(c = 1\) using Exercise (d).
Suppose \(A\) is an \(n\times n\) matrix and let \(\vec {v}\) be an eigenvector such that \(A\vec {v}=\lambda \vec {v}\). Also suppose
the characteristic polynomial of \(A\) is
\begin{equation*} \det \left ( z I-A\right ) =z ^{n}+a_{n-1} z ^{n-1}+\cdots +a_{1}z +a_{0} \end{equation*}
Use this to prove that
the Cayley-Hamilton theorem holds for any diagonalizable matrix \(A\). (The
Cayley-Hamilton theorem says that \(A\) satisfies its characteristic equation, i.e.,