Let \(A=\begin{bmatrix} -6 & -76 & -16 \\ 2 & 21 & 4 \\ -2 & -64 & -17 \end{bmatrix}\).
(a)
The vector \(\vec {v}_1=\begin{bmatrix}-4\\1\\-3\end{bmatrix}\) is an eigenvector of \(A\) because \(A\vec {v}_1= \lambda _1 \vec {v}_1\) where \(\lambda _1 = \)
-3 -1 2
(b)
The vector \(\vec {v}_2=\begin{bmatrix}8\\-2\\7\end{bmatrix}\) is an eigenvector of \(A\) because \(A\vec {v}_2= \lambda _2 \vec {v}_2\) where \(\lambda _2 = \)
-3 -1 2
(c)
The vector \(\vec {v}_3=\begin{bmatrix}4\\-1\\4\end{bmatrix}\) is an eigenvector of \(A\) because \(A\vec {v}_3= \lambda _3 \vec {v}_3\) where \(\lambda _3 = \)
-3 -1 2
(d)
Since the Power Method converges to the dominant eigenvector, it can be used to approximate which eigenvector of \(A\)?
\(\vec {v}_1\) \(\vec {v}_2\) \(\vec {v}_3\)

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