You are about to erase your work on this activity. Are you sure you want to do this?
Updated Version Available
There is an updated version of this activity. If you update to the most recent version of this activity, then your current progress on this activity will be erased. Regardless, your record of completion will remain. How would you like to proceed?
Mathematical Expression Editor
We determine if a function is analytic using the Cauchy-Riemann equations.
We say that is analytic at if is differentiable on for some . Furthermore, is called
analytic on a region if it is analytic at each point in .
example 1 Recall from section 3.2 that the function is differentiable at and nowhere
else. Thus, is not differentiable on any disk of positive radius. Hence, is nowhere
analytic.
(problem 1) Where is the function analytic?
Complete the sentence: is differentiable
on the real axis onlyon the imaginary
axis onlyon both the real and imaginary axesat the origin onlynowhere
Complete the sentence: is analytic
on the real axis onlyon the imaginary axis
onlyon both the real and imaginary axesat the origin onlynowhere
Here is a video solution to problem 1:
_
example 2 The function is differentiable at every point in and hence it is analytic
everywhere in .
(problem 2a) Where is the function analytic?
on punctured planeon the slit planeon entire planeat the origin onlynowhere
(problem 2b) Where is the function analytic?
on punctured planeon the slit planeon entire planeat the origin onlynowhere
(problem 2c) Where is the function analytic?
on punctured planeon the slit planeon entire planeat the origin onlynowhere
Like the real variable case, an analytic function whose derivative is zero is a
constant.
Suppose is analytic in a disk, . If on , then is constant on .
Proof
First note that since on , the partial derivatives and are all zero
on the disk. Suppose with . Then on the horizontal segment between and ,
implies that is constant on the segment and on the segment implies that
is constant on the segment as well. Now suppose with . Then on the vertical
segment between and , implies that is constant on the segment and on the
segment implies that is constant on the segment as well. Finally, any two points
can be connected by a horizontal and a vertical segment and is constant on
these segments, so . Since and were arbitrary, is constant on .
In a vane similar to the previous theorem, if the modulus of an analytic function is
constant, then the function itself is constant.
Suppose is analytic in a disk . If on , then is constant on .
Proof
If , the is identically zero, so suppose . The definition of modulus gives
Taking the partial derivative of both sides with respect to and with respect
to gives the system Dividing by and using the Cauchy-Riemann equations
selectively gives Multiplying the first equation by and the second equation by
gives adding these equations together gives which gives on . We could have
eliminated instead of which would have led to on . Hence is constant on .
Moreover, by the Cauchy-Riemann equations and on and so is constant on
as well. Thus is constant on .
(problem 3a) Solve the system for :
A function that is analytic at every point in is called entire.
(problem 3b) Select all of the functions below which are entire.