028405…: “Under a lime eyes”

$\newenvironment {prompt}{}{} \newcommand {\accordion }[0]{} \newcommand {\ungraded }[0]{} \newcommand {\xmDefaultPreamble }[0]{xmPreamble.tex} \newcommand {\xmDefaultPrintstyle }[0]{xmPrintstyle.sty} \newcommand {\todo }[0]{} \newcommand {\oiint }[0]{{\large \bigcirc }\kern -1.56em\iint } \newcommand {\mooculus }[0]{\textsf {\textbf {MOOC}\textnormal {\textsf {ULUS}}}} \newcommand {\sagemath }[0]{\textsf {SageMath}} \newcommand {\surfaceColor }[0]{violet} \newcommand {\surfaceColorTwo }[0]{redyellow} \newcommand {\sliceColor }[0]{greenyellow} \newcommand {\vector }[1]{\left \langle #1\right \rangle } \newcommand {\sectionOutcomes }[0]{}$

Here is the formula and graph of $V$.

\[ V(h) = \begin{cases} -2h-3 & \text { if } [-6, -2] \\ -(h+3)(h-3) & \text { if } (-2, 4] \\ \frac {7h}{4} - 8 & \text { if } (4,6) \end{cases} \]

Suppose the function $p$ is defined through the equation $p(m) = -2 V(m) + 5$.

What is the induced range of $p$?

\[ \left [ \answer {-13}, \answer {19} \right ] \]

2025-05-17 21:39:26