568469…: “Underneath a fine fact”

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\[ P(t) = \begin{cases} ln(t+8) & \text { on } (-8, -3] \\ -4 & \text { if } t = -2 \\ | t - 3 | - 4 & \text { on } (0, 8] \end{cases} \]

Shifted Domain

Define $M(y) = P(y - 2)$

The graph of $z = M(y)$ appears to be the graph of $y = P(t)$, just shifted left right by $\answer {2}$ units.

Shifted Domain

Define $x(f) = V(f + 3)$

The graph of $k = x(f)$ appears to be the graph of $y = P(t)$, just shifted left right by $\answer {3}$ units.

2025-05-18 07:10:23