Let \(M(k) = -3(k+2)^2 - 5\) be a quadratic function.

\(M'(k) = \answer {-6(k+2)}\).

\(M'(k) = 0\) at \(k = \answer {-2}\).

\(M'(k) > 0\) on \(\left ( \answer {-\infty }, \answer {-2} \right )\).

\(M'(k) < 0\) on \(\left ( \answer {-2}, \answer {\infty } \right )\).

\(M(k)\) increases on \(\left ( \answer {-\infty }, \answer {-2} \right )\).

\(M(k)\) decreases on \(\left ( \answer {-2}, \answer {\infty } \right )\).

The maximum of \(M(k)\) is located at \(k = \answer {-2}\).

2025-05-18 05:17:43