Let

\[ B(t) = 4 \cdot 2^{5t - 3} - 1 \]
\[ \lim \limits _{t \to \infty } B(t) = \answer {\infty } \]
\[ \lim \limits _{t \to -\infty } B(t) = \answer {-1} \]

Let

\[ h(z) = 4 \cdot 2^{-5z - 3} - 1 \]
\[ \lim \limits _{z \to \infty } h(z) = \answer {-1} \]
\[ \lim \limits _{z \to -\infty } h(z) = \answer {\infty } \]

Let

\[ f(y) = -4 \cdot 2^{5y - 3} - 1 \]
\[ \lim \limits _{y \to \infty } f(y) = \answer {-\infty } \]
\[ \lim \limits _{y \to -\infty } f(y) = \answer {-1} \]

Let

\[ H(x) = -4 \cdot 2^{-5x - 3} - 1 \]
\[ \lim \limits _{x \to \infty } H(x) = \answer {-1} \]
\[ \lim \limits _{x \to -\infty } H(x) = \answer {-\infty } \]
2025-01-07 02:16:42