Evaluate \(B(2) = \answer [tolerance=0.25]{-6}\)

Classify \(2\).

Classify \(-4\).

Classify \(-2\).

Classify \(7\).

\((-6, 7)\) is a global maximum of \(B\).

\((2, -6)\) is a global minimum of \(B\).

\(-6\) is a global minimum, which occurs how many times.

There exists a real number, \(M\), such that \(B(t) < M\) for all \(t\) in the domain.

For any \(\epsilon > 0\), there exists a domain number in the interval \((-9-\epsilon , -9+\epsilon )\).

For any \(\epsilon > 0\), there exists a domain number, \(d\), in the interval \((2-\epsilon , 2+\epsilon )\) such that \(B(d) > 4\).

The equation \(B(t) = 0\) has \(\answer {2}\) solutions.

The equation \(B(t) = 4\) has \(\answer {3}\) solutions.

The equation \(B(t) = 8\) has \(\answer {0}\) solutions.

The equation \(B(t) = -4\) has \(\answer {3}\) solutions.

The equation \(B(t) = -5\) has \(\answer {3}\) solutions.

The equation \(B(t) = -2\) has \(\answer {2}\) solutions.