Let \(f(x) = \frac {6x-1}{4 + 2x}\) with its natural domain.

Evaluate the following. (Use DNE for Does not Exist)

\begin{align*} f(0) &= \answer {-\frac {1}{4}} \\ f\left (\frac {1}{2}\right ) &= \answer {\frac {2}{5}} \\ f(-2) &= \answer {DNE} \\ f\left (\frac {1}{6}\right ) &= \answer {0} \\ f(-1) &= \answer {-\frac {7}{2}} \\ f(1) &= \answer {\frac {5}{6}} \end{align*}

Let \(G(t) = 3t - 5\) with its natural domain.

Evaluate the following. (Use DNE for Does not Exist)

\begin{align*} G(0) &= \answer {-5} \\ G\left (\frac {1}{2}\right ) &= \answer {-\frac {7}{2}} \\ G(-2) &= \answer {-11} \\ G\left (\frac {1}{3}\right ) &= \answer {-4} \\ G(-1) &= \answer {-8} \\ G(1) &= \answer {-2} \end{align*}

Let \(H(k) = 3 |2-k|-4\) with its natural domain.

Evaluate the following. (Use DNE for Does not Exist)

\begin{align*} H(0) &= \answer {2} \\ H\left (\frac {1}{2}\right ) &= \answer {\frac {1}{2}} \\ H(-2) &= \answer {8} \\ H(2) &= \answer {-4} \\ H(-1) &= \answer {5} \\ H(1) &= \answer {-1} \end{align*}

Let \(T(w) = 2 w^2 + 1\) with \([-2, 3)\) as its domain.

Evaluate the following. (Use DNE for Does not Exist)

\begin{align*} T(0) &= \answer {1} \\ T\left (\frac {1}{2}\right ) &= \answer {\frac {3}{2}} \\ T(-2) &= \answer {9} \\ T(4) &= \answer {DNE} \\ T(3) &= \answer {DNE} \\ T(1) &= \answer {3} \end{align*}